Details of the Path Within State Transition Diagram for Left
Descent to 27
The left descent assembly (descent to 27), ebsssbssbsbbssssbst,
provides a rich example of an itinerary in the state
diagram. Every internal node (D through H) is visited, and
some
(D,F,H) travel to different neighbors on different occasions.
l.d.a. elelement formula state step eqn 2 application transition
________________________ _____ ____ _________________ __________
2^ 3 * 3^18 * n + 445 5[8],1[3] b-step (4*445-1)/3 = 593 A->D
2^ 5 * 3^17 * n + 593 1[8],2[3] s-step (2*593-1)/3 = 395 D->F
2^ 6 * 3^16 * n + 395 3[8],2[3] s-step (2*395-1)/3 = 263 F->H
2^ 7 * 3^15 * n + 263 7[8],2[3] s-step (2*263-1)/3 = 175 H->G
2^ 8 * 3^14 * n + 175 7[8],1[3] b-step (4*175-1)/3 = 233 G->D
2^10 * 3^13 * n + 233 1[8],2[3] s-step (2*233-1)/3 = 155 D->F
2^11 * 3^12 * n + 155 3[8],2[3] s-step (2*155-1)/3 = 103 F->G
2^12 * 3^11 * n + 103 7[8],1[3] b-step (4*103-1)/3 = 137 G->D
2^14 * 3^10 * n + 137 1[8],2[3] s-step (2*137-1)/3 = 91 D->E
2^15 * 3^ 9 * n + 91 3[8],1[3] b-step (4* 91-1)/3 = 121 E->C
2^17 * 3^ 8 * n + 121 1[8],1[3] b-step (4*121-1)/3 = 161 C->D
2^19 * 3^ 7 * n + 161 1[8],2[3] s-step (2*161-1)/3 = 107 D->F
2^20 * 3^ 6 * n + 107 3[8],2[3] s-step (2*107-1)/3 = 71 F->H
2^21 * 3^ 5 * n + 71 7[8],2[3] s-step (2* 71-1)/3 = 47 H->H
2^22 * 3^ 4 * n + 47 7[8],2[3] s-step (2* 47-1)/3 = 31 H->G
2^23 * 3^ 3 * n + 31 7[8],1[3] b-step (4* 31-1)/3 = 41 G->D
2^25 * 3^ 2 * n + 41 1[8],2[3] s-step (2* 41-1)/3 = 27 D->leaf
2^26 * 3^ 1 * n + 27 0[3] leaf node ends the l.d.a.
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